(2x+3)(3x^2-19x+20)=0

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Solution for (2x+3)(3x^2-19x+20)=0 equation: 


Simplifying
(2x + 3)(3x2 + -19x + 20) = 0

Reorder the terms:
(3 + 2x)(3x2 + -19x + 20) = 0

Reorder the terms:
(3 + 2x)(20 + -19x + 3x2) = 0

Multiply (3 + 2x) * (20 + -19x + 3x2)
(3(20 + -19x + 3x2) + 2x * (20 + -19x + 3x2)) = 0
((20 * 3 + -19x * 3 + 3x2 * 3) + 2x * (20 + -19x + 3x2)) = 0
((60 + -57x + 9x2) + 2x * (20 + -19x + 3x2)) = 0
(60 + -57x + 9x2 + (20 * 2x + -19x * 2x + 3x2 * 2x)) = 0
(60 + -57x + 9x2 + (40x + -38x2 + 6x3)) = 0

Reorder the terms:
(60 + -57x + 40x + 9x2 + -38x2 + 6x3) = 0

Combine like terms: -57x + 40x = -17x
(60 + -17x + 9x2 + -38x2 + 6x3) = 0

Combine like terms: 9x2 + -38x2 = -29x2
(60 + -17x + -29x2 + 6x3) = 0

Solving
60 + -17x + -29x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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